IIT JEE / PMT Module Test 6 : Chemistry : d & f Block in Periodic Table

Normal type of MCQ with one correct option The first ionization energy of coinage family following the order:
Cu > Ag > Au
Cu > Au > Ag
Au > Cu > Ag
Au > Ag > Cu
Normal type of MCQ with one correct option HgCl2 and SnCl2 cannot coexist in a solution due to:
Common ion effect
Redox change
Solubility product
All of these
Normal type of MCQ with one correct option The dimerization of NO2 with lowering of temperature is accompanied by:
Darkening in color
Decrease in paramagnetism
Increase in P
None of these
Normal type of MCQ with one correct option Na2SO4 solution on boiling with flowers of sulphur gives:
NaHSO4
Na2S
Na2SO4
Na2S2O3
In this question, there may be more than one option correct Zn and Ag can be separated from each other by (A) Distillation (B) Heating with conc. NaOH (C) Treatment with dil. HNO3 (D) Treatment with conc. H2SO4
A,B
B
C,D
A,B & D
Comprehension The stability of complexes depends upon stability constant. Higher the value of stability constant more will be stability of complex. It can also be determined with the help of dissociation constant. Higher the value of dissociation constant, lesser will be stability. Smaller cation, with higher charge can form more stable complex. Stronger the ligand, more stable will be the complex. Polydenate ligands form more stable complex than unidentate ligand. If multidentate ligand is cyclic, it further increases the stability, it is called macrocyclic effect. Which of the following is most stable?
[Co(en)3]3+
[Co(NH3)6]3+
[Co(H2O)6]3+
[CoF6]3-
Comprehension The stability of complexes depends upon stability constant. Higher the value of stability constant more will be stability of complex. It can also be determined with the help of dissociation constant. Higher the value of dissociation constant, lesser will be stability. Smaller cation, with higher charge can form more stable complex. Stronger the ligand, more stable will be the complex. Polydenate ligands form more stable complex than unidentate ligand. If multidentate ligand is cyclic, it further increases the stability, it is called macrocyclic effect. Which of the following compound and liquid at room temperature?
Cr(CO)6
[Co(CO)4]2
Mn2(CO)10
Ni(CO)4
Comprehension The stability of complexes depends upon stability constant. Higher the value of stability constant more will be stability of complex. It can also be determined with the help of dissociation constant. Higher the value of dissociation constant, lesser will be stability. Smaller cation, with higher charge can form more stable complex. Stronger the ligand, more stable will be the complex. Polydenate ligands form more stable complex than unidentate ligand. If multidentate ligand is cyclic, it further increases the stability, it is called macrocyclic effect. Which of the following is called Wilkinson’s catalyst?
[(Ph3P)3Rh]Cl
TiCl4 + (C2H5)3Al
(C2H5)4Pb
[PtCl2(NH3)2]
ASSERTION(REASON A. [Co(NH3)5Cl]Cl2 reacts with excess of AgNO3 to form 2 moles of AgCl (white ppt) R. [Co(NH3)6Cl3 gives 2 moles of Cl- which react with AgNO3 to forms 2 moles of AgCl.
Both A and R are true and R is correct explanation of A
Both A and R are true and R is not correct explanation of A
A is true, R is false
A is false, R is true
Match matrix type of question:- Column I (A) Horn silver (B) Lunar caustic (C) Blue vitriol (D) White vitriol ColumnII (P) AgNO3 (Q) ZnSO4. 7H2O (R) AgCl (S) CuSO4.5H2O
(A) ( (Q); (B) ( (P); (C) ( (S); (D) ( (R);
(A) ( (D); (B) ( (P); (C) ( (S); (R) ( (Q);
(A) ( (R); (B) ( (P); (C) ( (S); (D) ( (Q);
(A) ( (R); (B) ( (Q); (C) ( (S); (D) ( (P);
Description:

This is the FREE Module test 6 of Chemistry; the covered chapter is d & f block of Periodic Table. Keep checking for Exclusive Paid Test series for IIT JEE and AIPMT from us at a very nominal cost at WiZiQ.com Happy Learning; all the best!

Discussion

Ananyo Chattopadhyay

Nice test. Want more like this. Good job.

2078 days 16 hours 36 minutes ago

Abhay

gud 1

4228 days 14 hours 13 minutes ago

ANI

NICE TEST

4398 days 16 hours 23 minutes ago

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