SOLUTIONS TO TEST OF POLYNOMIALS

SOLUTIONS TO TEST OF POLYNOMIALS SECTION A (OBJECTIVE)The degree of a constant term is 0 since 1,2,3 etc. can be represented by 1x0,2y0,3z0 respectively and so on.Thus, the answer is (d).1aaSECTION B the linear equation has 1 solution. the quadratic equation has 2 solutions.thus, degree of the polynomial is directly proportional to the number of solutions.(i) The sum of the squares of the base and height of a right angled triangle is equal to the square of hypotenuse.(ii) f(x) = (x+a) is divisible by g(x) if and only if f(0) = 0.by the remainder theorem,p(x) = x3+x2+8xg(x) = x+2remainder = p(0) = 03+02+8 x 0 = 0thus the remainder will be 0.(x+y)3/ (x+y) = (x+y)2 = x2 + 2xy + y2