20 solved step by step problems :Logarithm and exponentials.
LOGARITHM AND EXPONENTIALS. HOW TO WRITE AN EXPRESSION AS A LOGARITHM log means that , where a is called the base of the logarithm EXAMPLES Here a = 2, 5 32 2=32 So, log 32 5 ( Match the position of respective colours) logarithm base In other words you would say ‘ 2 to the power 5 equals 32’ Rewrite as logarithm Example 1 10 1000 log 1000 3 Example 2 5 625 log 625 4 Example 3 2 1024 log 1024 10 Example 4 log 1 0 (because) 1 Example 5 log 1(because) Find the value of Example 6: log 81 ? Let log 81 Therefore 3= 81 3 3 ( because 3 3 3 3 3 81 4 Therefore, log 81 4 . (when bases are same powers would be equal, if powers are equal bases would be same) Example 7: log 0.25 ? Let log 0.25 4 0.25 4 ( because 0.25=) 4 4 1 Therefore log 81 1 Ans. Example 8: log ? Let log = 5 Therefore, log 5 Ans. FIND THE VALUE OF X Example 9: 10 500 Applying log on both side, we get log 10 log 500 log 10 log 500 (because log dlog ) 1 log 500 (because log 10 1 log 500 2.70 (using calculator or log tables) LAWS OF LOGARITHMS MULTIPLICATION LAW log log log You can also say that when log applied on multiplication or product it would convert it, into sum of individual logs. Suppose that log log Rewriting with powers Multiplying the two equations : Rewriting as logarithm log log log log DIVISION LAW log log log POWER LAW log log WRITE AS A SINGLE LOGARITHM EXAMPLE 10 log 6 log 7=? SOLUTION log 6 log 7 log6 7 ( using multiplication law) log 42 EXAMPLE 11 log 15 log 3 SOLUTION log 15 log 3 log ( using division law) log log 5 EXAMPLE 12 2 log 3 3 log 2 SOLUTION First apply the power law to both the parts and then use the multiplication law 2 log 3 log3 log 9 (power law) 3 log 2 log2 log 8 Therefore, 2 log 3 3 log 2 log 9 log 8 log9 8 (multiplication law) log 72 EXAMPLE 13 log 3 4 log12 SOLUTION Use first the power law and then division law 4 log 12 log12 log Therefore, log 3 4 log12 log 3 log 1 16 log ( Division Law) log 48 Ans. ( 3 3 48) WRITE IN TERMS OF , , EXAMPLE 14 log SOLUTION log log log +log 2 log log 3log Ans. EXAMPLE 15 log y SOLUTION log = log log = log 3 log EXAMPLE 16 logxy z SOLUTION log log log log log log = log log log (b/c √ means and using power law) EXAMPLE 17 log SOLUTION log log log log 4log log 41 log 4 Ans. SOLVING EQUATIONS OF THE FORM EXAMPLE 18 Solve 3 20 SOLUTION To solve an equation means to find the value of unknown variable , therefore here we have to find the value of . Since your calculator has only base 10 logarithm and natural log (ln). So any working must be done in these two bases only. 3 20 log 3 log 20 ( Applying log on both sides) log 3 log 20 ( Applying power law) (dividing by log 3, to find . . 2.73 Ans. EXAMPLE 19 Solve 7 3 SOLUTION 7 3 Applying log on b.s 7 3 17 23 7 7 3 23 7 3 23 7 7 3 23 7 23 7 7 3 0.2966 Ans. Example 20: Solve 5 75 30 0 SOLUTION y 5 5 75 30 0 7 30 0 10 3 30 0 10 3 10 0 3 10 0 3 0 10 0 3 10 10 5 10, 3 , 5 3 log 5 log 3 log 5 log 3 log 3 log 5 0.68 Ans
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ADIL SHAMIMExperienced Mathematics and Accounts teacher.
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