LINEAR EQUATIONS IN ONE VARIABLE - Part 2 : LINEAR EQUATIONS IN ONE VARIABLE - Part 2 (With problems based on linear equations)
Slide 2 : Solution:
L.C.M of 4, 3, 2 = 12
TO SOLVE PROBLEMS BASED ON SIMPLE EQUATIONS : TO SOLVE PROBLEMS BASED ON SIMPLE EQUATIONS Find a number such that one-fifth of it is less than its one-fourth by 3.
Solution:
Let ‘x’ be the number.
One day a boy walked from his house to his school at the speed of and he reached 10 minutes late to the school. Next day he ran at a speed of and was 5minutes early to school. Find the distance between his house and the school. : One day a boy walked from his house to his school at the speed of and he reached 10 minutes late to the school. Next day he ran at a speed of and was 5minutes early to school. Find the distance between his house and the school. Let the distance between his house and school be x km
Time=
Time taken on the 1st day =
Time taken on the next day =
Difference in time = 10+5 =15 min =
2x-x =2
Slide 5 : In a shooting competition, a boy was to receive 20 paise for hitting the "bull's eye" and had to pay 8 paise for missing the "bull's eye". he tried 50 shoots but received only 48paise. how many times did he hit the "bull's eye. Let the boy hit the "Bull's eye" x times,
.:. He misses the " Bull's eye" (50-x) times.
For hitting the "Bull's eye" ,he receives 20x paise and for missing the "Bull's eye" he pays 8(50-x).
According to the given statement,
20x - 8(50-x) = 48
Slide 6 : Find three consecutive integers such that the smallest integer plus one-fifth of the next minus half of the third integer gives 9. Given: The required consecutive integers
= x , x+1 and x+2
= 14 , 14+1, 14+2
= 14 , 15 ,16
Slide 7 : TWO ARTICLES 'A' & 'B' TOGETHER COST RS. 2,226. IF ARTICLE 'A' COSTS 10% MORE THAN 'B', FIND THE COST OF EACH ARTICLE. Let the cost of article 'B' be Rs.x
Then cost of article 'A' =Rs.(x+10% of x)
Given:
Cost of article 'A'
Cost of article 'B' =Rs.x = Rs.1060
The sum of the digits of a 2 digit number is 9. if the number is divided by its unit digit the quotient is 6.find the number. : The sum of the digits of a 2 digit number is 9. if the number is divided by its unit digit the quotient is 6.find the number. Let the unit's digit = x
then ten's digit =9-x
Number =10(9-x) + x
=90 -10x + x =90 -9x
Given:
90 - 9x = 6x
90 = 6x + 9x 15x = 90
The required two digit number = 36