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Chemistry - Electrochemistry -Nernst equation

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Electrochemistry : Electrochemistry The study of the interchange of chemical and electrical energy. Sample electrochemical processes: 1) Corrosion 4 Fe(s) + 3 O2(g) ? 2 Fe2O3(s) 2) Biological processes C6H12O6 + 6 O2 ? 6 CO2 + 6 H2O 3) Batteries (Galvanic or Voltaic cells) Electrochemical cells that produce a current (flow of electrons) as a result of a redox reaction 4) Electrolytic cells Electrical energy is used to produce chemical change Used to prepare or purify metals (such as sodium, aluminum, copper)

Chemical Change ? Electron Flow : Chemical Change ? Electron Flow Copper: Cu(s), Cu2+(aq) Cu(s) ? Cu2+(aq) + 2e- ?G°rxn = ?G°f(Cu2+) = 65.6 kJ Silver: Ag(s), Ag+(aq) Ag(s) ? Ag+(aq) + e- ?G°rxn = ?G°f(Ag+) = 77.2 kJ Cu(s) ? Cu2+(aq) + 2e- ?G° = +65.6 kJ Ag+(aq) + e- ? Ag(s) ?G° = -77.2 kJ Cu(s) + 2 Ag+(aq) ? Cu2+(aq) + 2 Ag(s) ?G° = -88.8 kJ Spontaneous wmax = -88.8 kJ Cu2+ in solution 2( ) 2( ) Ag(s)

Harnessing the Energy : Harnessing the Energy Separate the half-reactions Creates a galvanic or voltaic cell Cu Ag 1 M CuSO4 Cu(s) ? Cu2+(aq) + 2e- 1 M AgNO3 Ag+(aq) + e- ? Ag(s) Luigi Galvani Alessandro Volta Cu2+ SO42- Ag+ NO3- KNO3(aq) salt bridge Oxidation Reduction Anode Cathode - (produces electrons) + (attracts electrons) Red Cat

Line Notation for Galvanic Cells : Line Notation for Galvanic Cells Cu Ag 1 M CuSO4 Cu(s) ? Cu2+(aq) + 2e- 1 M AgNO3 Ag+(aq) + e- ? Ag(s) Cu2+ SO42- Ag+ NO3- Oxidation Reduction Anode (-) Cathode (+) Anode always on the left Cu(s)?Cu2+ (1 M)??Ag+ (1 M)?Ag(s) Cathode always on the right

Chemical Change ? Electrical Work : Chemical Change ? Electrical Work Chemical change produces electrical energy Electrical energy can be used to do work! ?G = wmax Electrical work: w = -nFE n = # of moles e- transferred F = charge on a mole of e- E = electrical potential (electromotive force) Cell Potential (E) or Electromotive Force (emf): The driving force pushing the electrons from the anode to the cathode. Units = Volts 1 Volt = 1 joule/coulomb

Standard Reduction Potentials : Standard Reduction Potentials The cell potential E°cell can be determined from the standard reduction potentials (E°red) for the half-reactions: Reduction potential = tendency for reduction to happen Positive E°red ? spontaneous reduction reaction Negative E°red ? non-spontaneous reduction or spontaneous oxidation (reverse reaction) Standard (o) = standard conditions (1 M solutions, 1 atm gases)

Standard Reduction Potentials : Standard Reduction Potentials Half-Reaction E° (V) F2 + 2e- ? 2F- 2.87 Au3+ + 3 e- ? Au 1.50 Ag+ + e- ? Ag 0.80 Cu2+ + 2e- ? Cu 0.34 2H+ + 2e- ? H2 0.00 Ni2+ + 2e- ? Ni -0.23 Zn2+ + 2e- ? Zn -0.76 Al3+ + 3e- ? Al -1.66 Li+ + e- ? Li -3.05 ? E° = 0 (SHE) Standard Hydrogen Electrode E° > 0 Spontaneous reduction E° < 0 Non-Spontaneous reduction Reduction potential = tendency for reduction to happen Standard = standard conditions (1 M solutions, 1 atm gases) Spontaneous oxidation (reverse rxn)

Standard Reduction Potentials : Standard Reduction Potentials Half-Reaction E° (V) F2 + 2e- ? 2F- 2.87 Au3+ + 3 e- ? Au 1.50 Ag+ + e- ? Ag 0.80 Cu2+ + 2e- ? Cu 0.34 2H+ + 2e- ? H2 0.00 Ni ? Ni2+ + 2e- +0.23 Zn ? Zn2+ + 2e- +0.76 Al ? Al3+ + 3e- +1.66 Li ? Li+ + e- +3.05 E° > 0 Spontaneous reduction But remember, an oxidation CANNOT happen without a reduction Spontaneous oxidation

Standard Reduction Potentials : Standard Reduction Potentials Half-Reaction E° (V) F2 + 2e- ? 2F- 2.87 Au3+ + 3 e- ? Au 1.50 Ag+ + e- ? Ag 0.80 Cu2+ + 2e- ? Cu 0.34 2H+ + 2e- ? H2 0.00 Ni2+ + 2e- ? Ni -0.23 Zn2+ + 2e- ? Zn -0.76 Al3+ + 3e- ? Al -1.66 Li+ + e- ? Li -3.05 Strongest Oxidizing Agent (most easily reduced) Reduction potential = tendency for reduction to happen Standard = standard conditions (1 M solutions, 1 atm gases) Strongest Reducing Agent (most easily oxidized)

Cell Potential : Cell Potential E°cell = E°reduction + E°oxidation Ag+(aq) + e- ? Ag(s) E° = 0.80 V Cu2+(aq) + 2 e- ? Cu(s) E° = 0.34 V Reduction reaction: 2(Ag+(aq) + e- ? Ag(s)) E° = +0.80 V Oxidation reaction: Cu(s) ? Cu2+(aq) + 2 e- E° = - 0.34 V Cu(s) + 2 Ag+(aq) ? Cu2+(aq) + 2 Ag(s) E°cell = +0.46 V E° is intensive, unlike ?Go Cu(s)?Cu2+ (1 M)??Ag+ (1 M)?Ag(s) The E°cell MUST be + and thus spontaneous for Galvanic cells

Free Energy and Cell Potential : Free Energy and Cell Potential ?G? = wmax = ?nFE? n = number of moles of electrons transferred F = Faraday’s constant = 96,485 coulombs per mole of electrons (C/mol e-) E° = standard cell potential (V or J/C) Michael Faraday Cu(s)?Cu2+ (1 M)??Ag+ (1 M)?Ag(s) E°cell = +0.46 V ?G° = -nFE°cell ?G° = -(2 mol e-)(96485 C/mol e-)(0.46 V) ?G° = -88,800 J or -88.8 kJ

Practice Time : Practice Time Given the following information, draw a galvanic cell. Fe(s)?Fe2+(1 M)??Au3+(1 M)?Au(s) Be sure to include the following: Anode/Cathode reactions Balanced overall reaction Complete circuit (external wire with e- flow direction, salt bridge) Label all parts of the cell (solution, electrode, etc.)

Fe(s)?Fe2+(1 M)??Au3+(1 M)?Au(s) : Fe(s)?Fe2+(1 M)??Au3+(1 M)?Au(s) Fe Au 1 M Fe2+ Fe(s) ? Fe2+(aq) + 2e- 1 M Au3+ Au3+(aq) + 3e- ? Au(s) Fe2+ Au3+ Oxidation Reduction Anode Cathode 3Fe(s) + 2Au3+(aq) ? 3Fe2+(aq) + 2Au(s) cations E°cell = +0.440V (Fe rxn) + 1.50 V (Au rxn) = 1.94 V

Reaction Quotient : Reaction Quotient The reaction quotient (Q) sets up a ratio of products and reactants For a reaction, A + 2B ? 3C + 4D [C]3[D]4 [A]1[B]2 Only concentrations (aq) or pressures (g) are used to solve for Q Solids (s) and liquids (l) are not included in the expression Q =

Reaction Quotient practice : Reaction Quotient practice Write the Q expression for the following reaction CH4(g) + O2(g) ? CO2(g) + H2O(g) Reaction must be balanced first CH4(g) + 2O2(g) ? CO2(g) + 2H2O(g) (CO2)(H2O)2 (CH4)(O2)2 Q =

Reaction Quotient practice : Reaction Quotient practice Write the Q expression for the following reaction Cu(s) + 2Ag+(aq) ? Cu2+(aq) + 2Ag(s) (Cu2+)(Ag)2 (Cu)(Ag+)2 Is this correct? NO: Solids aren’t included in the equation! (Cu2+) (Ag+)2 Q = Q =

Non-standard conditions:The Nernst Equation : Non-standard conditions:The Nernst Equation We can calculate the potential of a cell in which some or all of the components are not in their standard states (not 1 M concentration or 1 atm pressure). ?G = ?G° + RT lnQ ?G = -nFE ?G° = -nFE° -nFE = -nFE° + RT lnQ Walther Nernst R = 8.3415 J/mol K T = temperature n = moles of e- F = Faraday’s constant 96,485 C/mol e-

Practice with the Nernst Equation : Practice with the Nernst Equation What will be the cell potential E of a Cu/Ag cell using 0.10 M Cu2+ and 1.0 M Ag+ solutions at 25°C? Cu(s) + 2 Ag+(aq) ? Cu2+(aq) + 2 Ag(s) E = 0.46 V – (-0.03 V) Cu(s)?Cu2+ (0.10 M)??Ag+ (1.0 M)?Ag(s) E = 0.49 V

Brain Warmup : Brain Warmup Half-Reaction E° (V) Ag+ + e- ? Ag 0.80 Cu2+ + 2e- ? Cu 0.34 Zn2+ + 2e- ? Zn -0.76 Al3+ + 3e- ? Al -1.66 What is E° for each of the following reactions? Which reaction(s) are spontaneous? 3 Ag+(aq) + Al(s) ? 3 Ag(s) + Al3+(aq) Cu2+(aq) + Zn(s) ? Cu(s) + Zn2+(aq) 2 Al3+(aq) + 3 Zn(s) ? 2 Al(s) + 3 Zn2+(aq) E° 2.46 V 1.10 V -0.90 V Spontaneous? Y Y N Zn can reduce Cu2+, but not Al3+

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George Kalgreadis
Chemistry and Physics teacher for IB and GCE A-level courses
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