Slide 1 : From the information we find the position of A,B,C points. The interferometer can be simplified as the below screen source1 source2 Source1 and source2 are identical. Source 1 is virtual because of path difference made by birefringent material. Location of position is represented by angle theta. Two paths along which two rays of light is transferred from each sourcehave different lengths and its optical different length will be
Slide 2 : The center of screen has maximum intensity, 50n must be integer.
Slide 3 : Our light is polarized, and birefringent material is rotated 45 degree. For light polarized in H direction, refractive index is n For light polarized in H direction, refractive index is n-0.01 Polarization can be decomposed
to sum of two V H vectors component
Slide 4 : For component V, Path difference of two polarization is a half of wavelength that imply their phase difference is pi. Original After birefringent twice That means
Slide 5 : H V Polarization Mirror Orthogonal two polarized light cannot interfere as the form of field.
Slide 6 : When interfere can occur, Bright Dark When interfere can not occur, there is no interference fringe. Field sum Intensity sum a) Answer : (A,B,C) = (0.5I, 0.5I, 0.5I)
Slide 7 : Answer sheet : 0.5I 0.5I 0.5I
0 I 0
I I I
I I I
I I I