WizIQ helps you learn and teach online - any subject you can think of!
Join for FREE

Diagnostic Test/ Organic Chemistry

Add to Favourites
Post to:

ORGANIC CHEMISTRY DIAGNOSTIC TEST Prepared by David Jeffrey, Ph.D., Cost Benefit, LLC, www.costbenllc.com Online tutorials, virtual classroom, educational consultations, course development, course support materials, diagnostic tests, program and career advising Multiple choice. Circle the letter, a, b, c, or d, corresponding to the best answer: Lewis structures do not account for/provide: octets formal charges resonance molecular shape When more than one valid Lewis structure may be drawn for the same molecular formula, these multiple structures: must be isomers must be resonance forms must be either isomers or resonance forms must be octet rule exceptions Exceeding the octet rule: is possible for atoms that two lone electron pairs is possible for atoms that have three valance electrons is not possible is possible for third row and higher atoms The ‘octet rule’ is based on the special stability of: Group II elements Group IV elements Group VI elements Group VIII elements Multiple resonance forms: all refer to one molecule must all have the same ‘% contributions’ refer to multiple molecules do not have to all be valid Lewis structures ‘Skeletal structures’ have implied: formal charges double bonds hydrogens oxygens Carbon tetrachloride has the molecular formula, CCl4. It has a ______________ shape, from ____________ theory. trigonal planar, VSEPR square planar, Lewis structure tetrahedral, VSEPR octahedral, VSEPR Atoms hybridize their orbitals in order to: increase their acidity or improve orbital overlap improve overlap or achieve an octet achieve an octet or have resonance have resonance or increase acidity All alkanes: have the molecular formula, CnH2n+2 have the formula, CnH2n have no double or triple bonds none of the above A Bronsted-Lowry acid must: have a CO2H group somewhere in the molecule have an OH group...... must have a H....... must have a lone pair The stronger the acid, the…. greater the pKa smaller the pKa higher the pH smaller the Kab Alkanes undergo very few reactions. The reason for this is: their molecular weights are too small they don’t have enough carbon atoms they don’t have enough hydrogen atoms they lack functional groups Alkanes under combustion reactions with ____, to produce ___, ____, and ____. water, oxygen, CO2, energy. oxygen, chlorine radicals, water, carbon dioxide. oxygen, CO2, water, energy. bromine, radicals, oxygen, water. The three stages of a radical chain reaction are, in order: initiation, condensation, and termination deprotonation, propagation, and condensation initiation, propogation, and termination propogation, initiation, and termination For any given acid-base reaction, in order for the Kab to lie to the right: the pKa of the acid must be greater than the pKa of the conjugate acid the pKa of the acid must be less than the pKa of the conjugate acid the pKa of the conjugate acid must be less than the pKa of the acid the pH of the conjugate acid must be greater than the pH of the acid The combustion of an alkane is what type of general reaction? radical reaction acid-base reaction oxidation-reduction reaction none of the above “Conformers”: are another type of “isomer” involve torsional angle rotation involve bond angle rotation are non-superimposable mirror images Two substituents on a cyclohexane ring have a ‘cis-1,3’ relationship. This means they can be: axial, axial axial, equatorial equatorial, axial boat, chair We generally show relative stereochemistry using cyclic compounds because: acyclic compounds only have absolute stereochemistry cyclic compounds are generally more stable than acyclic cyclic compounds have fewer conformational states cyclic compounds have no bond angle strain Enantiomers: must be superimposable mirror images must have the same number of chiral carbons, but may have different achiral carbons cannot be separated have the same sign but different magnitudes of [] For a structure with “n” chiral carbons, but fewer than “2n” distinct stereoisomers, there must be: an axis of symmetry in the molecule an odd number of “n” an even number of “n” a ring in the structure Circle the molecule expected to prefer Sn2 over Sn1: Circle the alkyl halide expected to prefer Sn1 over Sn2: Circle the alkyl halide which may react via Sn1 or Sn2: Based on our lectures, which of the following methods does not tell us whether a secondary alkyl halide prefers Sn1 or Sn2? stereochemical test rate study detection of reactive intermediates changing the leaving group Any chemical reaction which results in the creation of one new chiral carbon, from an achiral reactant. and which lacks any special chiral catalyst or reagent: generally prefers the R-enantiomeric product must always give a racemic mixture of products generally prefers the S-enantiomeric product must always give a diastereomeric mixture of products “Syn” and “anti” refer to: regiochemistry of the E2 reaction double-bond substitution stereochemistry of the E2 reaction none of the above For a general alkene addition reaction, we are concerned with the regiochemistry only for: nonsymmetric alkene + symmetric “X-Y” nonsymmetric alkene + nonsymmetric “X-Y” symmetric alkene + symmetric “X-Y” symmetric alkene + nonsymmetric “X-Y” Consider the following reaction of some alkene: C6H10 + CH3CH2OH --------- (cat H+) -------> C8H16O What can you say about the structure of the product? must be a cyclic alcohol must be a cyclic ether must be an acyclic alcohol must be an acyclic ether Hydroboration of an nonsymmetric alkene results in: a Markovnikov alcohol as the major product a cis epoxide a trans epoxide an anti-Markovnikov alcohol as the major product The reaction of cis-2-butene with HBr gives: a cis epoxide mainly (2R)-2-bromobutane mainly (2S)-2-bromobutane racemic 2-bromobutane An “E1” reaction always involves a total of ____ steps: Two Three Four depends on the reactant An alcohol may be _________ to convert it into a better leaving group: “hydroborated” “tosylated” Reduced oxidized You react an acyclic molecule with H2SO4 and obtain a cyclic ether as the product. Your reactant must have been: an ‘alcohol alkene’ an ‘alcohol ether’ an ‘alkene bromide’ an ‘epoxide alkene’ Draw a valid Lewis structure for each molecular formula. Show the ‘full Lewis structure’, no shorthand conventions: 35) [C3H5O]- 36) HN3 37) C2Cl4 38) [O2]2- Convert each of the following Lewis structures to skeletal, or skeletal to Lewis, as indicated: Predict the following reactions by drawing the expected product(s) in the boxes provided. Ignore any stereochemical aspects. Your product(s) should be consistent with any additional reaction information which may be presented: Using the pKa table attached to the exam, or your basic qualitative knowledge of how structure affects acidity, draw the products of the following acid-base reactions in the boxes provided. Then, estimate the position of the acid-base equilibrium reaction by selecting the appropriate Kab choice: For each of the following two problems, circle one of the last four structures that has the indicated relationship to the first structure: For each of the following nucleophilic substitution reactions, draw the expected product(s) in the boxes provided. Show absolute and/or relative stereochemistry as applicable. Additional information or data may be provided for assistance: Explanation: 61) We never draw five or more bonds to carbon atoms in molecules. For an uncharged carbon, we always show four bonds: 4 single bonds, or 1 double and 2 singles, or 2 doubles, or 1 triple and 1 single….. ……WHY?! Provide an explanation for this rule, based on the electron configuration of a carbon atom, Valence Bond Theory (VBT), and any other related topics we’ve discussed in lecture: 62) The following reaction converts the cyclic hydrocarbon (A) to benzene (B) and hydrogen gas. While this is known to be an oxidation reaction, show, by oxidation states, that this is indeed true: 63) The radical halogenation of the alkene, propene, proceeds much more rapidly than the same reaction for propane. Additionally, the halogen atom is incorporated at a primary position in propene, while propane prefers the expected secondary halogenation. While we haven’t studied alkene chemistry, use what you know about the radical halogenation mechanism….and resonance….to propose an explanation for this observation. You may use a verbal explanation to support your proposed structures and mechanism, but this can’t be your sole explanation: For each of the following reactions, draw the expected product(s) in the boxes provided. Show absolute and/or relative stereochemistry as applicable. Your answers must be consistent with any additional information or data: Synthesis. Show the reactions you would use to go from the indicated starting material to the target molecule. You must show the expected product(s) from each of your proposed reaction steps: FOR A FREE ANALYSIS OF YOUR TEST RESULTS, EMAIL ME AT: djeffrey@costbenllc.com

Description
A comprehensive diagnostic test of the first semester of a typical undergraduate organic chemistry course, as developed by a highly experienced, PhD, American chemistry professor.

Comments
ochem
By: ochem
616 days 14 hours 14 minutes ago

helpful

Want to learn?

Sign up and browse through relevant courses.

Name:
Your Email:
Password:
Country:
Contact no.:


Area code Number
Subject you are interested in:
Word verification: (Enter the text as in image)


Sign Up Already a member? Sign In
I agree to WizIQ's User Agreement & Privacy Policy
2 Members Recommend
15 Followers

Your Facebook Friends on WizIQ