: EXAMPLE 3 Standardized Test Practice SOLUTION 7p + 13 = 9p – 5 13 = 2p – 5 18 = 2p 9 = p Write original equation. Subtract 7p from each side. Add 5 to each side. Divide each side by 2.
Slide 2 : EXAMPLE 3 Standardized Test Practice CHECK 7p + 13 = 9p – 5 76 = 76? Write original equation. Substitute 9 for p. Multiply. Solution checks.
Slide 3 : EXAMPLE 4 Solve an equation using the distributive property Solve 3(5x – 8) = –2(–x + 7) – 12x. 3(5x – 8) = –2(–x + 7) – 12x 15x – 24 = 2x – 14 – 12x 15x – 24 = – 10x – 14 25x – 24 = –14 25x = 10 Write original equation. Distributive property Combine like terms. Add 10x to each side. Add 24 to each side. Divide each side by 25 and simplify.
Slide 4 : EXAMPLE 4 Solve an equation using the distributive property CHECK – 18 = – 18? Simplify. Solution checks.
Slide 5 : EXAMPLE 5 Solve a work problem SOLUTION
Slide 6 : EXAMPLE 5 Solve a work problem 3t + 4t = 168 7t = 168 t = 24 Write equation. Multiply each side by the LCD, 24. Distributive property Combine like terms. Divide each side by 7.
Slide 7 : EXAMPLE 5 Solve a work problem CHECK
Slide 8 : GUIDED PRACTICE for Examples 3, 4, and 5 Solve the equation. Check your solution. 5. –2x + 9 = 2x – 7 6. 10 – x = –6x + 15 7. 3(x + 2) = 5(x + 4)
Slide 9 : GUIDED PRACTICE for Examples 3, 4, and 5 Solve the equation. Check your solution. 8. –4(2x + 5) = 2(–x – 9) – 4x
Slide 10 : GUIDED PRACTICE for Examples 3, 4, and 5 Solve the equation. Check your solution.