Slide 1 : Solutions Presented By:- Ritesh Kesharwani Sir Mona Modern Hr.Sec.School Sarangarh Chhattisgarh ( http:// mona.250free.com) 1.Homogeneous Mixture and Hetrogeneous Mixture
2.Binary,Trinary,Tetranary etc.
3.Solvent and Solute.
4.Concentration= Solute/Solvent or Solvent
5.Scales to show conc.=
1.%(Percentage)
1.A. % ( pph) weight of solute x 100 / “weight” of solvent
1.B. W/V% weight of solute x 100 / “Volume” of solvent
2. Molarity (M) 1gm mole dissolve in 1 litre soln.
“ M = WMV/ 1000”
Slide 2 : 3.Normality:- (N) 1gm Equivalent dissolve in 1 liter soln.
“ N = ENV/ 1000”
4.Molality:- (m) 1gm-mole dissolve in 1000gm wolvent
“ m = 1000 X Wb/ Mb X Wa”
5. Mole Fraction:- (X) A=Solvent, B= Solute
XA= NA/NA+NB & XB= NB/NA+NB { N=W/M}
6.Formality(F)= FFV/1000( use full for ionic solid)
7.PPM = weight of solute x 10 / Total Mass 6 Solutions Presented By:- Ritesh Kesharwani Sir Mona Modern Hr.Sec.School Sarangarh Chhattisgarh ( http:// mona.250free.com)
Slide 3 : Solutions Special relationship :-
1.Molarity = m x density of solution
(1 + m) x Mol.weight of solute
2.Molality = M
Density of solution – (M x mol weight of solute)
3.Normality x Eq.weight = Molarity x Mol weight
4. Mole Fraction of solute = m x mol weight of solvent
(1 + m) x mol weight of solvent
5. Mole Fraction of solute = M x mol weight of solvent
M(mw of solvent-mw of solute) x d Presented By:- Ritesh Kesharwani Sir Mona Modern Hr.Sec.School Sarangarh Chhattisgarh ( http:// mona.250free.com)
Slide 4 : Solutions Presented By:- Ritesh Kesharwani Sir Mona Modern Hr.Sec.School Sarangarh Chhattisgarh ( http:// mona.250free.com) // Origin of Vapor Pressure //
Factors:- 1.Nature of solvent
2.Temprature
3.Presence of Non-Volatile Solute
Slide 5 : Solutions Presented By:- Ritesh Kesharwani Sir Mona Modern Hr.Sec.School Sarangarh Chhattisgarh ( http:// mona.250free.com) Roult’s Law:- Ideal Solutions
Slide 6 : Solutions Presented By:- Ritesh Kesharwani Sir Mona Modern Hr.Sec.School Sarangarh Chhattisgarh ( http:// mona.250free.com) -:Non-Ideal Solutions:- 1. P > PA + PB
2. dHmix > 0
3. dVmix > 0 1. P < PA + PB
2. dHmix < O
3. dVmix < 0
Slide 7 : Solutions Presented By:- Ritesh Kesharwani Sir Mona Modern Hr.Sec.School Sarangarh Chhattisgarh ( http:// mona.250free.com) Colligative Properties:-
1.Relative Lowering of Vapor Pressure
2.Osmotic Pressure
3.Elevation in B.P.
4. Depression in F.P.
Slide 8 : Solutions Presented By:- Ritesh Kesharwani Sir Mona Modern Hr.Sec.School Sarangarh Chhattisgarh ( http:// mona.250free.com) 2.Osmotic Pressure:- After Some time……….. ?Osmotic Pressure Isotonic Solution
Slide 9 : Solutions Presented By:- Ritesh Kesharwani Sir Mona Modern Hr.Sec.School Sarangarh Chhattisgarh ( http:// mona.250free.com) 3.Elevation in B.P. “ m = 1000 X Wb/ Mb X Wa”
Slide 10 : Presented By:- Ritesh Kesharwani Sir Mona Modern Hr.Sec.School Sarangarh Chhattisgarh ( http:// mona.250free.com) Solutions “ m = 1000 X Wb/ Mb X Wa” 4. Depression in F.P.
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