� 22. Double integrals Definition 22.1. Let R =[a,b] × [c,d] ⊂ R2 be a rectangle in the plane. A partition P of R is a pair of sequences: a = x0 0, we may find a δ> 0 such that for every mesh P whose mesh size is less than δ, we have |I − S| < �, where S is any Riemann sum associated to P. We write ��f(x,y)dx dy = I,R to mean that f is integrable with integral I. We use a sneaky trick to integrate over regions other than rectangles. Suppose that D is a bounded subset of the plane. Then we can find a rectangle R which completely contains D. Definition 22.4. The indicator function of D ⊂ R is the function iD : R 1−→ R, � �� � �� �� given by iD(x)= 1 if x ∈ D 0 if x/∈ D. If iD is integrable, then we say that the area of D is the integral iD dx dy. R If iD is not integrable, then D does not have an area. Example 22.5. Let D = { (x,y) ∈ [0, 1] × [0, 1] | x,y ∈ Q }. Then D does not have an area. Definition 22.6. If f : D −→ R is a function and D is bounded, then pick D ⊂ R ⊂ R2 a rectangle. Define f˜: R −→ R, by the rule f˜(x)= f(x) if x ∈ D 0 otherwise. We say that f is integrable over D if f˜ is integrable over R. In this case �� �� f(x,y)dx dy = f˜(x,y)dx dy. D R Proposition 22.7. Let D ⊂ R2 be a bounded subset and let f : D −→ R and g : D −→ R be two integrable functions. Let λ be a scalar. Then (1) f + g is integrable over D and �� �� �� f(x,y)+ g(x,y)dx dy = f(x,y)dx dy + g(x,y)dx dy. D DD (2) λf is integrable over D and λf(x,y)dx dy = λf(x,y)dx dy. D D (3) If f(x,y) ≤ g(x,y) for any (x,y) ∈ D, then �� �� f(x,y)dx dy ≤ g(x,y)dx dy. D D 2 �� �� (4) |f| is integrable over D and | D f(x,y)dx dy|≤ D|f(x,y)| dx dy. It is straightforward to integrate continuous functions over regions of three special types: Definition 22.8. A bounded subset D ⊂ R2 is an elementary region if it is one of three types: Type 1: D = { (x,y) ∈ R2 | a ≤ x ≤ b,γ(x) ≤ y ≤ δ(x) }, where γ :[a,b] −→ R and δ :[a,b] −→ R are continuous functions. Type 2: D = { (x,y) ∈ R2 | c ≤ y ≤ d,α(y) ≤ x ≤ β(y) }, where α :[c,d] −→ R and β :[c,d] −→ R are continuous functions. Type 3: D is both type 1 and 2. Theorem 22.9. Let D ⊂ R2 be an elementary region and let f : D −→ R be a continuous function. Then (1) If D is of type 1, then �� � b �� δ(x) � f(x,y)dx dy = f(x,y)dy dx. D aγ(x) (2) If D if of type 2, then �� � d �� β(y) � f(x,y)dx dy = f(x,y)dx dy. D cα(y) Example 22.10. Let D be the region bounded by the lines x =0, y =4 and the parabola y = x2 . Let f : D −→ R be the function given by f(x,y)= x2 + y2 . 3 If we view D as a region of type 1, then we get �� � 2 �� 4 � f(x,y)dx dy = x 2 + y 2 dy dx D 0 x2 � 2� 3 �4 = x 2 y + ydx 30 x2 � 2 26 x6 =4x 2 +3 − x 4 − 3dx 0� 4x3 26xx5 x7 �2 = 3+3 − 5 − 37· 0 25 27 25 27 =3+3 − 5 − 37· 26 28 =+ 35 7·�� 122 =26 + . 35 7· On the other hand, if we view D as a region of type 2, then we get �� � 4 �� √y � f(x,y)dx dy = x 2 + y 2 dx dy D 00 � 4� 3 �√yx=+ xy 2 dy300� 4 y3/2 =+ y 5/2 dy30 ��4 2y5/2 2y7/2 =+ 35 7· 0 26 28 =+ 35 7·�� 122 =26 + . 35 7· 4 MIT OpenCourseWarehttp://ocw.mit.edu 18.022 Calculus of Several Variables Fall 2010 For information about citing these materials or our Terms of Use, visit: http://ocw.mit.edu/terms.
Description
Riemann sum, indicator function are defined and explained. The conditions under which a function is integrable are stated. Types of bounded regions which will also be known as elementary region, are discussed. Examplesare given to explain the theorems on double integral.
Prof. James McKernan, Maths, 18.022. Calculus of Several Variables, Fall 2010: 22. Double integrals: Massachusetts Institute of Technology: MIT OpenCourseWare),http://ocw.mit.edu (Accessed October17, 2011). License: Creative Commons BY-NC-SA:http://ocw.mit.edu/terms/#cc