Electricity and Magnetism--Current Electricity
Topics: Conductivity and resistivity 8.022 (E&M) – Lecture 7 Electrical currents Ohm’s law in microscopic and macroscopic form 2 Electric current I i Units: cgs: esu/s C/s=ampere (A) 9 dQI dt = G. Sciolla – MIT 8.022 – Lecture 7 Consider a region in which there is a flow of charges: E.g. cylndrical conductor We define a current: the charge/unit time flowing through a certain surface SI: Conversion: 1 A = 2.998 x 10esu/s 13 Current density J Velocity of each charge: u ∆Q /∆t where ∆ cosprismqnV qnAI qnt t t t θ∆ ∆ ∆ = = = = = = ∆ ∆ ∆ ∆ i i A ut∆ θ J qnu uρ≡ ≡ lume charge densiG. Sciolla – MIT 8.022 – Lecture 7 Number density: n = #charges /unit volume Current flowing through area A: I = Q= q x number of charges in the prism Where we defined the current density J as: Q q N u t uA JA ΝΒ: ρ=voty 4 More realistic case… ii u Multiple charge carriers: liind of i k iik i average velocity J: kkk kk k k J uρ≡ ≡∑ ∑ 1 ()k ik u uN = ∑ kk k k k k k J uρ≡ ≡∑ ∑ S I= ∫ i G. Sciolla – MIT 8.022 – Lecture 7 We made a number of unrealistic assumptions: only 1 knd of charge carriers: we could have several, e.g.: + and – ons assumed to be the same for all particles: unrealistic! regular surface with J constant on it E.g.: souton with different kons NB: + ion with velocity uis equivalent to – on with velocty -uVelocity: Not all charges have the same velocty Arbitrary surface S, arbitrary qnu k i qn u JdA 25 Non standard currents Other kinds of currents (Demo F5) + + + + ----Na+ Cl-G. Sciolla – MIT 8.022 – Lecture 7 We usually think of currents as electrons moving inside a conductor This is only one of the many examples! Ions in solution such as Salt (NaCl) in water 6 The continuity equation Some charge exits S J J J J J JS Q t ∂=− ∂∫ i 00S V V V J tQt t J t ρ ρ ρ ⎧ = ∇ ⎪ ∂⎪ ⎛ ⎞ ⇒ ∇ + = ⇒⎨ ⎜ ⎟∂ ∂ ∂ ∂∇ + ⎝ ⎠⎪ = − = ∂ ∂⎪⎩ ∂− ∫ ∫ ∫ ∫ i i i i G. Sciolla – MIT 8.022 – Lecture 7 A current I flows through the closed surface S: Some charge enters What happens to the charge after it enters? Piles up inside Leaves the surface NB: -because dA points outside the surface Apply Gauss’s theorem and obtain continuity equation: inside JdA inside JdA JdV dV dV 37 Thoughts on continuity equation For steady currents: ρ S J J J J J J 0J t ρ∂∇+ = ∂ i 0J∇ = i G. Sciolla – MIT 8.022 – Lecture 7 Continuity equation: What does it teach us? Conservation of electric charges in presence of currents no accumulation of charges inside the surface: d/dt=0 8 Microscopic Ohm’s law Electric fields cause charges to move conductivity σ J Eσ= e G. Sciolla – MIT 8.022 – Lecture 7 Experimentally, it was observed by Ohm that Microscopic version of Ohm’s law: It reflects the proportionality between E and J in each point Proportionality constant: More stuff here pleas 49 in E //L σMacroscopic Ohm’s lawRI V LV IJ E A AL Rσ σ σ =⇒ ≡= ⇒ = A L J E G. Sciolla – MIT 8.022 – Lecture 7 Current is flowing in a uniform material of length L uniform electric field Potential difference between two ends: V=EL Ohm’s law J=E holds in every point: where Resistance R Proportionality constant between V and R in Ohm’s law R ≡ L Aσ ≡ L A ρ Units: [V]=[R][I] SI: Ohm (Ω) = V/A cgs: s/cm Dependence on the geometry: Inversely proportional to A and proportional to L Dependence on the property of the material: Inversely proportional to conductivity G. Sciolla – MIT 8.022 – Lecture 7 10 5 Resistivity ρ = 1/σ Units: in SI: Ω Depends on chemistry of material, ,… Demos F1 and F4 Resistivity G. Sciolla – MIT 8.022 – Lecture 7 11 Describes how fast electrons can travel in the material m; in cgs: s temperature Demos F1 and F4 Why? Room temperature: ρ when T i ρ increases Very low temperature: material Resistivity vs. Temperature ρ T G. Sciolla – MIT 8.022 – Lecture 7 12 Does resistivity depend on T? depends upon collisional processes ncreases more collisions Mean free path dominated by impurities or defects in the ~ constant with temperature. With sufficient purity, some metals become superconductors 6 σ E Spherical symmetry φ φ φ ): Application: Resistance of a spherical shell ρ Difference in potential V current φ φ =0 Q: what is the resistance R? b a V ρ () B r A r φ = + 1() ab a r Vφ ⎛ ⎞ = −⎜ ⎟− −⎝ ⎠ 2 2 1 1ˆ() ab abEr V r J Vσ= ⇒ = − − 4 44 ab V VI V abba I V ba baR abπσ πσ πσ = = = ⇒ = = = − − −∫ i i G. Sciolla – MIT 8.022 – Lecture 7 13 Microscopic Ohm will hold: J=spherical potential: Boundary conditions: (a)=V and (b)=0 E=-grad(2 concentric spheres; material in between has resistivity inner=V; outerV=0 ba r b a ba r b a r Sphere J dA J A What if σ is not constant? ivity σ 1 and σ 2 Eli i σ q l11 2 2I AEσ σ= = σ 1 σ 2 I 2 1 2 1( ) 4 4 4q E E E I A ρ ρσ π π π − − = = = G. Sciolla – MIT 8.022 – Lecture 7 14 Cylindrical wire made of 2 conductors with conductWhat is the consequence? Current flowing must be the same in the whole cylinder ectric fields are dfferent in the 2 regions E dscontinuous surface layer at the boundary When conductivity changes there is the possibility that some charge accumulates somewhere. This is necessary to maintain steady fow. A E surface 7Thoughts on Ohm’s law In plain Engli A constant el ll i and are scattered the average behavior is a uniform drift J Eσ= E v∝ F ma E a= ⇒ ∝ E G. Sciolla – MIT 8.022 – Lecture 7 15 Ohm’s law in microscopic formulation: sh: ectric field creates a steady current: Does this make sense? Charges are moving in an effectively viscous medium As sky diver in free fa: first accelerate, then reach constant v Why? Charges are accelerated by E but then bump into nucleMotion of electrons in conductor E i0: Impull The average momentum is: ii ial 0p = Ep = 1 1 1 1 1 1( ) N N N i i i i i i i p m u qE tN N N= = = = = + = +∑ ∑ ∑ 1 0 N i i u = →∑ 1 1 N i i t N τ = ≡ ∑ 1 N i i qEmu tN τ = = ≡∑ G. Sciolla – MIT 8.022 – Lecture 7 16 N electrons are moving in a material immersed in Two components contribute to the momentum: Random collision velocty use due to eectric field: For large N: Where is the average tme between 2 collsions Property of the materRandom mu qEt m u mu qEt qE 8Conductivity For multiple carriers: 2 = u qE nqE m mmu τ τσ σ τ ⎧ =⎪ ⇒ = ⇒ =⎨ =⎪⎩ 2 1 N kk k i k nq m τσ = =∑ G. Sciolla – MIT 8.022 – Lecture 7 17 From this derivation we can read off the conductivity Jnq Jnq qE 9
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The main topics are electrical currents, conductivity and resistivity , Ohm;s law in macroscopic and microscopic form. Flow of electric currents, nature of charge carrier, continuity equations are explained.Ohm's law, resistance , resistivity, resistance of spherical shell, conductivity forms a part of the topic. The consequences of non-uniform charge density on flow of current is explained.
Prof. Prof.Gabriella Sciolla, 8.0222 Physics II: Electricity and Magnetism, Massachusetts Institute of Technology: MIT OpenCourseWare),http://ocw.mit.edu (Accessed Sept 5th,2011). License: Creative Commons BY-NC-SA: http://ocw.mit.edu/terms/#cc
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