18.01 Calculus Jason Starr Fall 2005 Lecture 2. September 9, 2005Homework. Problem Set 1 Part I: (f)–(h); Part II: Problems 3.Practice Problems. Course Reader: 1C22 1C33 1C44 1D33 1D551. Tangent lines to graphs. For y = f(x), the equation of the secant line through (x0, f(x0)) and (x0 + Δx, f(x0 + Δx)) is, y = f(x0 + Δx) − f(x0)(x − x0) + f(x0). Δx In the limit, the equation of the tangent line through (x0, f(x0)) is, y = f�(x0)(x − x0) + y0. Example. For the parabola y = x2, the derivative is, y�(x0) = 2x0. The equation of the tangent line is, y = 2x0(x − x0) = 2x0x − x2 0. For instance, the equation of the tangent line through (2, 4) is, y = 4x − 4. 2Given a point (x, y), what are all points (x0, x0) on the parabola whose tangent line contains (x, y)? To solve, consider x and y as constants and solve for x0. For instance, if (x, y)= (1, −3), this gives, 2(−3) = 2x0(1) − x0, or, 2 x0 − 2x0 − 3 = 0. 18.01 Calculus Jason Starr Fall 2005 Factoring (x0 − 3)(x0 + 1), the solutions are x0 equals −1 and x0 equals 3. The corresponding tangent lines are, y = −2x − 1, and y = 6x − 9. For general (x, y), the solutions are, x0 = x ± � x2 − y. 2. Limits. Precise definition is on p. 791 of Appendix A.2. Intuitive definition: limxf (x)→x0 equals L if and only if all values of f (x) can be made arbitrarily close to L by choosing x sufficiently close to x0. One interpretation is the “microscope/laser illuminator” analogy: An observer focuses a microscopes fieldofvie on a thin strip parallel to the xaxxi centered on y = L. The goal of the illuminator is to focus a laserbeea centered on x0 parallel to the yaxxi (but with the line x = x0 deleted) so that only the portion of the graph in the fieldofvie is illuminated. If for every magnification of the microscope, the illuminator can succeed, then the limit is defined and equals L. There is a beautiful Java applet on the webpage of Daniel J. Heath of Pacific Lutheran University, http://www.plu.edu/~heathdj/java/calc1/Epsilon.html If you use this, try a = −1. For lefthaan limits, use a laser that illuminates only to the left of x0. For righthaan limits, use a laser that illuminates only to the right of x0. 3. Continuity. A function f (x) is continuous at x0 if f (x0) is defined, limxf (x) is →x0 defined, and limxf (x) equals f (x0). Also, f (x) is continuous on an interval if it is contin↭x0 uous at every point of the interval. The types of discontinuity are: removable discontinuity, jump discontinuity, infinite discontinuity and essential discontinuity.
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To calculate the equation of the secant line is explained here.Few problems are solved to show the process to find the tangent lines to a given graph. Limits, left hand and right hand limits and the continuity are defined in this lecture note. The types of discontinuity are discussed.
Prof. Jason Starr, Maths, 18.01 Single Variable Calculus, Fall 2005: 2. Slope and Derivative, Limits and Continuity, Massachusetts Institute of Technology: MIT OpenCourseWare),http://ocw.mit.edu (Accessed July 28,2011). License: Creative Commons BY-NC-SA:http://ocw.mit.edu/terms/#cc
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