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Paper consists of 50 question which are required to be finished in an hours time.
A starts 3 Minutes after B for a place 4.5km distant. B, on reaching his destination, immediately returns and after walking a km meets A. If A can walk 1 Km in 18 minutes,then what is B's speed?- Solution please.
20 days 9 hours 14 minutes ago
A covers 3.5 km before meeting B.So time taken for it is = [18 * 3.5] + 3 = 66 minsB covers 5.5 km [11/2 km] before meeting A in 66 mins i.e., [66/60] hours = time takenB's speed = [d/t] = [ 11/2 ]/ [11/10] = 5 km/hr
20 hours 18 minutes ago
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