Weight of oxalic acid required to cpmpletely neutralise 50 ml of 0.5 N NaOH (Mol.Wt of oxalic acid=126)
1)1.575 gr
2)0.1575 gr
3)15.75 gr
4)63 gr
2)Normality of0.98%H2SO4 is mixed with 400 ml. of 1N HCl and the solution is made up to1000 ml.Normality of the resulting solution is
1) 0.3 N
2) 0.1 N
3) 0.2 N
4)0.44 N
3) The number of milli- equivalents in 100 ml. of 0.5 N HCl solution is
1) 100
2) 50
3) 25
4) 0.5
4) A dilute aqueous solution of glucose will have a vapour pressure which is
1) more than that of water
2) less than that os water
3) equal to that of water
4) much greater than that of water
5) Asseron (A) ; For an easily volatile liquid the vapour pressure of the liquid is relatively high at room temperature.
Reason (R) ; The inter moecular forces of attraction are high among easily volatile liquids
1) Both (A) are( R) are true and (R) is the correct explanation of (A)
2) Both (A) are( R) are true but (R) is not the correct explanation of (A)
3) (A) is true but (R) is not true .
4) is not true but (R) is true .
6) The PH of a 0.1M solution of weak monoprotic acid i s 5.0 .The value of (H+ )ion cocentration and Ka respectively are
1) 1*10^-5, 1*10^-10
2) 1*10^-1 , 1*10^-5
3) 1*10^-5 , 1*10^-9
4)1*10^-8 , 1*10^-10
6)250 ml. of 0.01 M HCl is mixed with 250 ml. of 0.05 M NaOH and the mixture is diluted to 1 litre. The PH of the resulting solution is
1) 2
2) 12
3) 10
4) 4
7) Lewis base is
1) BF3
2) SnCl4
3) CO2
4) NO