Scholarship Test for IIT-JEE, AIEEE, PMT (VIII TO XII) CHEMISTRY - Alcohol, Phenol, Aldehyde Ketone Test - 2


A neutral compound with molecular formula C3H8O evolves H2 when treated with sodium metals & gives idoform test. The compound is
(CH3)2CHOH
CH3CH2CH2OH
CH3COCH3
CH3CH2CHO
Primary, secondary & tertiary alcohols may be distinguished by
Fehling solution test
Victor–Meyer test
Hoffmann test
Beilstein test
Methanol cannot be dried over anhydrous CaCl2 because
CaCl2 dissolves in it
It is not a good dehydrating agent
It forms a solid alcoholate of formula CaCl2.4CH3OH
It reacts with CaCl2 to form calcium methoxide
Increasing pKa values of o, m & p cresols is
o < p < m
m < p < o
m < o < p
p < o < m
Sulphonation of phenol with conc. H2SO4 at 288–293 K gives
O–phenolsulphonic acid
Sulphanilic acid
P–Phenolsulphonic acid
Sulphone

O–Bromophenol
P-Bromophenol
m–Bromophenol
2,4,6–Tribromophenol
Compound having maximum hydrogen bonding is
Acetic acid
Glycerol
Ethyl alcohol
Ethylene glycol

Wurtz reaction
Williamson’s synthesis
Kolbe’s reaction
Hofmann bromide reaction

Reimer–Tiemann reaction
Schotten–Baumann reaction
Acetylation
Benzoylation

CH3CH2CH2OH
CH3CHOHCH3
CH3OCH2CH3
CH3CH2CHO
The compound obtained by the reaction of Ethene with diborane following by hydrolysis
Ethanol
Propanol
Ethanal
Triethyl boride


CH3COCH2CH3
CH3CH2CH2CHO
(CH3)2CHCHO
CH3CH2CH2CH2OH
A position isomer of 2–pentanone is
3–Pentanone
3–Methyl–2–butanone
1–Pentanal
2,2–Dimethyl propanal
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Description:

Scholarship Test for IIT-JEE, AIEEE, PMT (VIII TO XII) CHEMISTRY - Alcohol, Phenol, Aldehyde Ketone Test - 2

Tags:

IIT JEE  AIEEE  AIPMT  AFMC  CBSE

Comments
tejinderchauhan
By: tejinderchauhan
553 days 7 hours 49 minutes ago

plse give answer

prashanth
By: prashanth
452 days 8 hours 11 minutes ago

ok

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